How to create instance from generic type

It’s easy to explain this in code.

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public <T> void myMethod(List<T> list) {     T t; //  t = new T();   // This is basically what you want,                    // but will cause compile error.   }

Strictly speaking, you can NOT create instances of type parameters. But you can reach the same goal by using reflection and one more parameter.

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public <T> void myMethod(List<T> list, Class<T>cls) {     T t; //  t = new T();   // This is what you want to do                    // but will cause compile error.     try {       t = cls.newInstance();  // use reflection to create instance     } catch (InstantiationException | IllegalAccessException e) {       e.printStackTrace();     }   }

This is how to invoke the method.

1 2	List<String> myList = new ArrayList<>(); myMethod(myList,String.class);