How to create instance from generic type

It’s easy to explain this in code.

  public <T> void myMethod(List<T> list) {
    T t;
//  t = new T();   // This is basically what you want,
                   // but will cause compile error.
  }

Strictly speaking, you can NOT create instances of type parameters. But you can reach the same goal by using reflection and one more parameter.

  public <T> void myMethod(List<T> list, Class<T>cls) {
    T t;
//  t = new T();   // This is what you want to do
                   // but will cause compile error.
    try {
      t = cls.newInstance();  // use reflection to create instance
    } catch (InstantiationException | IllegalAccessException e) {
      e.printStackTrace();
    }
  }

This is how to invoke the method.

  List<String> myList = new ArrayList<>();
  myMethod(myList,String.class);